To create the checkerboard pattern, an element should be a 1 if the sum of its row and column indices is even (or odd, depending on the desired starting color). Use the modulus operator to check this condition: if (row + col) % 2 == 0: grid[row][col] = 1 Use code with caution. Copied to clipboard : Sets the element to 1 . Odd sum (row + col) : Leaves the element as 0 . 4. Print the Result
The core challenge is making the colors alternate. A square's color depends on the sum of its row and column indexes: If (row + column) is even , use Color A. If (row + column) is odd , use Color B. 9.1.7 Checkerboard V2 Python Solution 9.1.7 checkerboard v2 answers
Ensure your loops start at 0 and use the strictly less than operator ( < rows ), or start at 1 and use less than or equal to ( <= rows ). Mixing these up will distort the grid boundaries. To create the checkerboard pattern, an element should
Tracks the horizontal movement across each row.For every single row, the inner loop runs completely from left to right. 3. Coordinate Calculation Odd sum (row + col) : Leaves the element as 0
logic is the most efficient way to solve version 2 of this problem. In "v1," you might have only alternated colors per row, but adding the row and column indices together ensures that if you are on an even row, the pattern starts with "Color A," and if you are on an odd row, it starts with "Color B." ✅ Final Result The answer is achieved by using nested for loops combined with the conditional statement if (row + col) % 2 == 0